4y^2-24y+20=0

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Solution for 4y^2-24y+20=0 equation: 



4y^2-24y+20=0

a = 4; b = -24; c = +20;
Δ = b2-4ac
Δ = -242-4·4·20
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-16}{2*4}=\frac{8}{8}
=1
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+16}{2*4}=\frac{40}{8}
=5
$

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